7a^2+9a+1=0

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Solution for 7a^2+9a+1=0 equation: 



7a^2+9a+1=0

a = 7; b = 9; c = +1;
Δ = b2-4ac
Δ = 92-4·7·1
Δ = 53
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{53}}{2*7}=\frac{-9-\sqrt{53}}{14}
$


$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{53}}{2*7}=\frac{-9+\sqrt{53}}{14}
$

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